Bash How to Pass Arguments

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Bash How to Pass Arguments

The special shell variable “$@” represents a list of all arguments that is passed to the script.

If you want to pass all arguments to your function, you can use this syntax:

function_name "$@"

If you want to pass all arguments to another script, you can use this syntax:

script_mame "$@"

Let’s take an example called passit.sh. In this script, we defined function print_argument, that print argument that comes from the command line:

#!/bin/bash

# function's definition
function PRINT_ARGUMENTS()
{
echo "Arguments of shell are: $@"
}

# in this place we want to call function
PRINT_ARGUMENTS "$@"

Let’s try to execute passit.sh in this way:

chmod u+x ./passit.sh
./passit.sh aa bb cc

Output: Arguments of the shell are: aa bb cc

You can see that function obtains all shell arguments, which were written in the bash command line.

To get a number of arguments use:

echo "Number of arguments of shell are: $#"

It is often used to check if a required number is equal to some value.

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